The Student Room Group

Circumference of parametric ellipse?

Ok so I've got this question that I dunno how to do the first part.

An ellipse has parametric equations
x=cos(t),y=(3)sin(t)2x=cos(t), y=\frac{\sqrt(3)sin(t)}{2}.

Show that the length of its circumference is given by
20π2((3+sin2(t))dt2\int_0^\frac{\pi}{2}(\sqrt(3+sin^2(t)) dt
(thats the part i dont understand)

The integral cannot be evaluated in terms of elementary functions. USe the trapezium rule with interval-halving to evaluate it to 6dp. (<- I can do this part)
--

I've never done anything like the first part before :s

I found a formula s=ab(1+dydx2)dxs=\int_a^b \sqrt(1+\frac{dy}{dx}^2) dx

not sure if it's any good for this

all i done so far is find
dxdt=sin(t)\frac{dx}{dt}=-sin(t)
dydt=(3)sint(t)2\frac{dy}{dt}=\frac{\sqrt(3)sint(t)}{2}
(edited 13 years ago)

Quick Reply

Latest