Hey there! Sign in to join this conversationNew here? Join for free
    • Thread Starter
    Offline

    0
    ReputationRep:
    Does anyone know how to rearrange this exponential equation to find the value of x. i have put in all the known values:

    50/100 = 2.718 to the -0.2733x

    Need to work out x. i am expecting it to be 2.55.

    any help greatly appreciated!!!
    Offline

    15
    ReputationRep:
    (Original post by bizzy25)
    Does anyone know how to rearrange this exponential equation to find the value of x. i have put in all the known values:

    50/100 = 2.718 to the -0.2733x

    Need to work out x. i am expecting it to be 2.55.

    any help greatly appreciated!!!
    If you have a calculator which you can do log_{a}b then its just:

    log_{2.718}0.5 = -0.6932190565 = -0.2733x

x = 2.536476606

    It is valid rearranging to take log_{2.718} of both sides, because that is in inverse function of 2.718^x


    If you do not have a calculator with that function, then you can do:
    log_{2.718}0.5 = \dfrac{ln(0.5)}{ln(2.718)} = -0.6932190565 and then continue as above.
 
 
 
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    What newspaper do you read/prefer?
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Quick reply
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.