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# Stats help please (binomial).. Watch

1. The correction test is 0.038 and 10 randomly selected components define the distribution, the probability that:

-none of the components fail the test?

How do you do this? =\
2. None fail = all 10 pass.
P(pass)=1- P(fail)
3. (Original post by Get me off the £\?%!^@ computer)
None fail = all 10 pass.
P(pass)=1- P(fail)
So would that be 10*(0.038)^0 * (1-0.038)^10 = 6.788 (3dp) ?
4. (Original post by Nkhan)
So would that be 10*(0.038)^0 * (1-0.038)^10 = 6.788 (3dp) ?
No, the 10 should not be there. There is only one way for all 10 to pass.
5. (Original post by Get me off the £\?%!^@ computer)
No, the 10 should not be there. There is only one way for all 10 to pass.
So its just 0.038)^0 * (1-0.038)^10 ?
6. Yes.
7. (Original post by Get me off the £\?%!^@ computer)
Yes.
ahh okays thanks x

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