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    When lead is melted at atmospheric pressure the melting point is 327.0 degrees C, the density decreases from 1.101 x 10^4 to 1.065 x 10^4 kg/m^3 and the latent heat is 24.5 kJ/kg. Estimate the melting point of lead at a pressure of 100 atm.

    My attempt:

    Ok so Im not sure what formula/principle im meant to use to work this out.

    I've worked out the energy expended per m^3 at 1atm to be 8820 kJ/m^3... what do i do now Thanks
 
 
 
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