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1. Please can someone help me with this question, i don't even know where to start!

Given that f(x) = (x-2) (x^3 + ax^2 + bx + c) find the values of the constants a, b and c.

Thankyouu
2. (Original post by stanmoor)
Please can someone help me with this question, i don't even know where to start!

Given that f(x) = (x-2) (x^3 + ax^2 + bx + c) find the values of the constants a, b and c.

Thankyouu
You need to give us the rest of the question otherwise you are going to get some pretty unhelpful responses.
3. (Original post by Mr M)
You need to give us the rest of the question otherwise you are going to get some pretty unhelpful responses.
This.

Though from what I can see, it will probably involve long division...
4. (Original post by stanmoor)
Please can someone help me with this question, i don't even know where to start!

Given that f(x) = (x-2) (x^3 + ax^2 + bx + c) find the values of the constants a, b and c.

Thankyouu
I'm sorry but what type of maths is this?
5. Throw in any values you want, YOU CAN'T BE WRONG.

Now that's Maths for you.
6. I agree that it looks like long division, and surely there's more to the question..
7. I have a better one :

a, b and c are constants

find them
8. (Original post by kaosu_souzousha)
I have a better one :

a, b and c are constants

find them
Haha. I reckon they are 2, 26 and 1,203,123.
9. How accurate was my first post?

I'm psychic me.
10. (Original post by stanmoor)
Please can someone help me with this question, i don't even know where to start!

Given that f(x) = (x-2) (x^3 + ax^2 + bx + c) find the values of the constants a, b and c.

Thankyouu
f(2) = 8+4a+2b+c
you need another (x- something) bracket to find the second equation. After this has been done , you can then solve simultaneously to find A, B and C.... normally its just a and b.... are you sure this is the full question and you havent left anything out?
11. (Original post by StephenP91)
Haha. I reckon they are 2, 26 and 1,203,123.
12. (Original post by MissCandyFloss)
f(2) = 8+4a+2b+c
you need another (x- something) bracket to find the second equation. After this has been done , you can then solve simultaneously to find A, B and C.... normally its just a and b.... are you sure this is the full question and you havent left anything out?
you do realise that

f(2) = 0 ?

f(2) = ( 8 + 4a + 2b + c ) * ( 0 ) = 0
13. I think you put a couple of values in for x and then solve simultaneously.
14. (Original post by kaosu_souzousha)
you do realise that

f(2) = 0 ?

f(2) = ( 8 + 4a + 2b + c ) * ( 0 ) = 0
ohhhhh hes multiplying both brackets! lol i thought (x-2) was a factor... oops!

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