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    Hi im studying for C1, i came across a question

    (1296)^1/4

    i know the answer is -+6 through using a calculator, but im just wondering in an exam is there a method anyone could show me to work this out because i obviously wont be able to use a calculator

    any help is really appreciated

    thanks
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    (Original post by afc_22)
    Hi im studying for C1, i came across a question

    (1296)^1/4

    i know the answer is -+6 through using a calculator, but im just wondering in an exam is there a method anyone could show me to work this out because i obviously wont be able to use a calculator

    any help is really appreciated

    thanks
    Seems quite a strange question for C1 if I'm honest, I wouldn't expect a number quite that high to quad-root (I don't know how to say it properly)


    But if you got something like this in the exam, you can pretty much be certain it would be a whole number solution, seeing as it's non-calculator so really all I would advise is trial and error, trying 3, 4, 5 etc and you'd get the solution. That's all I can offer for advice, sorry!
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    Prime factorisation:

    1296 = 2 \times 648 = 2^2 \times 324 = 2^3 \times 162 = 2^4 \times 81 = 2^4 \times 3^4

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    by the way, the answer is 6 not \pm6
 
 
 
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