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    How would you go about doing this question?

    1.2g Mg reacts with excess sulphuric acid. Calculate the volume of Hydrogen produced at room temperature and pressure.

    1. Write Balanced equation
    so...Mg (s) + h2S04 (aq) ----> MgS04(aq) + H2(g)

    1.2/24 = 0.05 moles

    0.05 x 24 = 1.2dm cubed...is this correct?

    Thanks!
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    (Original post by me_myself_and_I)
    How would you go about doing this question?

    1.2g Mg reacts with excess sulphuric acid. Calculate the volume of Hydrogen produced at room temperature and pressure.

    1. Write Balanced equation
    so...Mg (s) + h2S04 (aq) ----> MgS04(aq) + H2(g)

    1.2/24 = 0.05 moles

    0.05 x 24 = 1.2dm cubed...is this correct?

    Thanks!
    yup, you got moles of magnesium

    Then moles of hydrogen equivalent from the equation (it's the same, 1:1 ratio)

    And then into volume at RTP

    so ......
 
 
 
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