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Integration (Chemistry) help.

My problem is I dont know what to do, its not the integration that I need help with; if someone can help me through the question i.e. where to start?

Thanks.
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Simply evaluate the integral:

∫300900(258.2+5.82×10−2T−6.28×10−6T−2) dT\displaystyle \int_{300}^{900} (258.2 + 5.82\times10^{-2}T - 6.28\times 10^{-6}{T^{-2}})\ dT
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J_Alom
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Original post by EierVonSatan
Simply evaluate the integral:

∫300900(258.2+5.82×10−2T−6.28×10−6T−2) dT\displaystyle \int_{300}^{900} (258.2 + 5.82\times10^{-2}T - 6.28\times 10^{-6}{T^{-2}})\ dT


after doing so, i ended up with 1.62x10^5 joules per kelvin per mole (3s.f.) {i think thats the units)

that can't be the right answer! can it? helpppp me my fellow chemist!!!
(edited 13 years ago)
Original post by J_Alom
after doing so, i ended up with 1.62x10^5 joules per kelvin per mole (3s.f.)

that can't be the right answer! can it? helpppp me my fellow chemist!!!


It's an enthalpy calculation so you've got those units wrong - would the value look more reasonable in kJ mol-1? :p:

If you look at the major contributor then 258.2(900-300) = 154920 which isn't far off from what you have :smile:
Reply 4
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J_Alom
OP
Original post by EierVonSatan
It's an enthalpy calculation so you've got those units wrong - would the value look more reasonable in kJ mol-1? :p:

If you look at the major contributor then 258.2(900-300) = 154920 which isn't far off from what you have :smile:


ohhhhhh; thanks for that!

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