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    Can someone help me answer these questions; i've tried them, but the answers seems to be wrong

    3(2x+3y-1)-2(3x-2y-4)

    and

    4y^2+5y-6

    Thanks
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    What do you have to do with these expressions? Do you have to factorise them, make them equal to zero and solve them or something else?
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    (Original post by ttoby)
    What do you have to do with these expressions? Do you have to factorise them, make them equal to zero and solve them or something else?
    With the first one; 3(2x+3y-1)-2(3x-2y-4)
    I need to simplify it to give an expression.

    With the second one; 4y^2+5y-6
    I need to factorise it.
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    (Original post by iitsMee..x)
    With the first one; 3(2x+3y-1)-2(3x-2y-4)
    I need to simplify it to give an expression.

    With the second one; 4y^2+5y-6
    I need to factorise it.
    ok well for the first one just try and multiply out the brackets and collect the terms

    6x + 9y - 3 -6x + 4y + 8
    13y + 5

    and the second one

    find 2 numbers which multiply to give -24 and 2 numbers that add to give you 5

    which would be 8 and 3 so you can split up your equation

    4y^2 + 8y - 3y - 6

    and factorise from here

    4y(y+2)-3(y+2)
    (4y-3)(y+2)

    so y=3/4 or y=-2
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    (Original post by Mr_Muffin_Man)
    ok well for the first one just try and multiply out the brackets and collect the terms

    6x + 9y - 3 -6x + 4y + 8
    13y + 5

    and the second one

    find 2 numbers which multiply to give -24 and 2 numbers that add to give you 5

    which would be 8 and 3 so you can split up your equation

    4y^2 + 8y - 3y - 6

    and factorise from here

    4y(y+2)-3(y+2)
    (4y-3)(y+2)

    so y=3/4 or y=-2
    Thanks so much; that actually explained it all. Sorry to be bother, but would you mind helping me with one last question I can't getmy head around.
    how can I simplify;
    3a^2b*(2ab^-2)^3/4ab^2
    Sorry & Thank You.
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    (Original post by iitsMee..x)
    Thanks so much; that actually explained it all. Sorry to be bother, but would you mind helping me with one last question I can't getmy head around.
    how can I simplify;
    3a^2b*(2ab^-2)^3/4ab^2
    Sorry & Thank You.
    Just to make sure I'm reading your post right, you want to simplify 3a^2b(2ab^{-2})^{3/4}ab^2?

    Start by simplifying the brackets: (2ab^{-2})^{3/4}=2^{3/4}a^{3/4}(b^{-2})^{3/4}=2^{3/4}a^{3/4}b^{-3/2}

    Then simplify the whole expression using the indices rule: a^xa^y=a^{x+y}.
 
 
 
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