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    A wire of length 2.6m and constant diameter 0.80 mm is made of steel with a Young modulus of 2.0 x 10^11 Pa. The wire is stretched so that its length increases by 1.2 mm. Assuming that the change is elastic, calculate for this wire:

    1) The force applied at each end of the wire.

    How would you do this? :confused:

    I worked out the strain as being 4.62 x 10^-4 and the applied strain as being 92300000. Any ideas?
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      (Original post by adil12)
      A wire of length 2.6m and constant diameter 0.80 mm is made of steel with a Young modulus of 2.0 x 10^11 Pa. The wire is stretched so that its length increases by 1.2 mm. Assuming that the change is elastic, calculate for this wire:

      1) The force applied at each end of the wire.

      How would you do this? :confused:

      I worked out the strain as being 4.62 x 10^-4 and the applied strain as being 92300000. Any ideas?
      Use Young Modulus = stress / strain
      Stress is Force / Area of cross section
      Strain = increase in length / original length

      You can work out area of cross section from the diameter.
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      (Original post by Stonebridge)
      Use Young Modulus = stress / strain
      Stress is Force / Area of cross section
      Strain = increase in length / original length

      You can work out area of cross section from the diameter.
      Right, so I would then just re-arrange the formula and do 92300000 x (0.0004^2 x Pi) = 46.4 N as the answer?
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        (Original post by adil12)
        Right, so I would then just re-arrange the formula and do 92300000 x (0.0004^2 x Pi) = 46.4 N as the answer?
        Yes, that's it.
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        (Original post by Stonebridge)
        Yes, that's it.
        Awesome thank you :cool:
       
       
       
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