- Thread Starter
Last edited by TheEd; 10-12-2010 at 16:59.
- 05-12-2010 11:48
(Original post by TheEd)
- 05-12-2010 12:12
Parametrising the curve as follows:
How do I do this integration?
Apparently the integrand is a derivative of a function of the form where is a 2nd order polynomial.
You will get a fraction which maybe integrated with another substitution and/or breaking into part fractions
- 05-12-2010 12:44
add 1 to the power and divide by the power