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Very short binomial question, help appreciated! :D Watch

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    Hi

    what does 'expand (1+6x)^2 for 5 non zero terms
    What does that mean? :/
    that isn't the real question, i've used it so as not to add my actual question, as it's not really that part of the question i need help with-if that makes sense.

    Thanks
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    It means the first 5 terms (constant, x, x^2 etc) that do not equal zero. The more terms you have, the closer it is to the original form.
    The example you gave, (1+6x)^2, expands to 1+12x+36x^2 so I'm a little confused. You would usually have a non-natural number as your exponent for the question to make sense.

    The green is very hard to read... :P
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    What board you with?
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    (Original post by CallumCameron)
    It means the first 5 terms (constant, x, x^2 etc) that do not equal zero. The more terms you have, the closer it is to the original form.
    The example you gave, (1+6x)^2, expands to 1+12x+36x^2 so I'm a little confused. You would usually have a non-natural number as your exponent for the question to make sense.

    The green is very hard to read... :P
    Sorry about the green
    so, if my expansion part i have: 1 + 3/2ax + 3/8a^2x^2...., is that what they mean by non zero terms? and if it's '5 non zero terms' then it's upto x^6, right?

    Thanks alot
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    (Original post by dream123)
    Sorry about the green
    so, if my expansion part i have: 1 + 3/2ax + 3/8a^2x^2...., is that what they mean by non zero terms? and if it's '5 non zero terms' then it's upto x^6, right?

    Thanks alot
    Yes, that's what they mean. Although it should be up to x^4 as the constant is also included. If you do come across a term that does equal zero, just add an extra term on the end so you still have 5. Eg, if x^3 had a coefficient that was zero, x^5 would be the fifth non-zero term.

    Hope that helps!
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    (Original post by CallumCameron)
    Yes, that's what they mean. Although it should be up to x^4 as the constant is also included. If you do come across a term that does equal zero, just add an extra term on the end so you still have 5. Eg, if x^3 had a coefficient that was zero, x^5 would be the fifth non-zero term.

    Hope that helps!
    Ah righty!
    Thank you very much, rep is on its way
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    (Original post by dream123)
    Ah righty!
    Thank you very much, rep is on its way
    Glad I could help
 
 
 
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