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# Absolute value inequalities *Grr* help appreciated :D Watch

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1. Hi,

Inequalities are an absolute pain, but add absolute values and well...

Anyway, I've just made up a question so the question I really need to answer isn't answered for me (though, that would be great-it wouldn't really help a great deal!)
So, if we need to solve the following inequality:

I begin with writing:

0 <
Should I multiply each side by (x+1) ?? because after this step, I'm completely unsure what to do :/

Any help appreciated!
2. LOL, no one?
3. Everything is incorrect.

Hint: If x = -2 ?

Remember you can use positive real numbers without affecting the inequality, viz. if a < b and x is positive ax < bx where as negative x gives ax > bx.
4. (Original post by DeanK22)
Everything is incorrect.

Hint: If x = -2 ?

Remember you can use positive real numbers without affecting the inequality, viz. if a < b and x is positive ax < bx where as negative x gives ax > bx.
Nope. Nothing. I'm officially lost
5. (Original post by dream123)
Nope. Nothing. I'm officially lost
If x = -2 we have |x+2| = 0 which better not be in the denominator.

As |y| => 0 for all y (and > 0 if y =/= 0 ) we multiply by the positive |x+2| to obtain

That occurs iff x < 0 and x-3 > 0 or x > 0 and x - 3 < 0

Spoiler:
Show
Generally if a > 0 the quadratic ax^2 + bx + c is less than zero in the interval between its root if multiple roots exist.

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Updated: December 7, 2010
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