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    hi, just need help on a simple question, my mind's gone blank!

    caco3 + 2hcl --> cacl2 + h2o +co2

    7.50 x 10^-3 mol caco3 reacts with 0.2 mol dm hcl

    calculate the volume in cm3 of 0.2mol dm-3 hcl required to react with 7.5 x 10^-3mol caco3


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    (Original post by insideedge)
    hi, just need help on a simple question, my mind's gone blank!

    caco3 + 2hcl --> cacl2 + h2o +co2

    7.50 x 10^-3 mol caco3 reacts with 0.2 mol dm hcl

    calculate the volume in cm3 of 0.2mol dm-3 hcl required to react with 7.5 x 10^-3mol caco3


    Thanks
    Too blank to find the shift key obviously...

    You have any idea how to start?
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    (Original post by charco)
    Too blank to find the shift key obviously...

    You have any idea how to start?
    nope
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    (Original post by insideedge)
    nope
    You are given the moles of CaCO3

    You first have to work out how many moles of HCl this reacts with using the equation.
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    (Original post by charco)
    You are given the moles of CaCO3

    You first have to work out how many moles of HCl this reacts with using the equation.
    oh yeah, thanks, so volume hcl(aq) works out at 75 and volume co2 180cm3.

    Thanks
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    (Original post by insideedge)
    oh yeah, thanks, so volume hcl(aq) works out at 75 and volume co2 180cm3.

    Thanks
    Mol HCl = 2 x mol CaCO3 = 1.5 x 10-2

    Moles = molarity x volume (litres)

    1.5 x 10-2 = 0.2 x vol

    vol = 7.5 x 10-2 = 75 cm3
 
 
 
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