You are Here: Home >< Maths

# Euler equation Watch

1. How do I use the euler equation (x=e^t) to integrate this:

(x^2 D^2 +x D -4)y = x^3

This may be me being stupid but am I supposed to sub in for each x e^nt .. but then what?

Also for those who don't know, D = dy/dx

Thanks.
2. (Original post by Carlo08)
How do I use the euler equation (x=e^t) to integrate this:

(x^2 D^2 +x D -4)y = x^3

This may be me being stupid but am I supposed to sub in for each x e^nt .. but then what?

Also for those who don't know, D = dy/dx

Thanks.
x=e^t
dy/dx=e^-t(dy/dt)
d^2y/dx^2=e^-2t(d^2y/dt^2 - dy/dt)

sub into ur eqn gives

y(d^2y/dt^2)-4y-e^3t=0

rearrange and solve as nonhomogenous second order linear differential eqn ? :\

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: December 8, 2010
Today on TSR

Find out how.

### Want £10K to start a business?

Discussions on TSR

• Latest
• ## See more of what you like on The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

• Poll
Useful resources

### Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

### How to use LaTex

Writing equations the easy way

### Study habits of A* students

Top tips from students who have already aced their exams

## Groups associated with this forum:

View associated groups
Discussions on TSR

• Latest
• ## See more of what you like on The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

• The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.