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# Simple Maths Show that ... Watch

1. Show that the curve y= (2x-1)^2 only meets the x axis at the point (0.5, 0)
2. b^2-4ac=0
put 0.5 into the equation and you get y=0
when y=0 you cross the x axis
3. differentiate it and you find that x=0.5, plug that value into original equation to get y=0
4. when crosses the x axis (y=0): therefore in the equation for curve y=(2x-1)^2

--> 0 = (2x-1)^2
--> 0=(2x-1) (square root bothe sides)
-->2x = 1 therefore x = 0.5
therefore crosses x axis at the point (0.5,0)
5. just think of it graphically. If you have x-intercept= 0.5, y must have a value of zero

so sub in y as 0 and you get: 0 = (2x-1)(2x-1) << solve it and you can only get a value of 0.5, so the coordiantes are (0.5, 0)
6. Simple maths shows that...
Maths is useful in everyday life.

Complex maths shows that...
Maths is useless in everyday life.
7. (Original post by asem93)
Show that the curve y= (2x-1)^2 only meets the x axis at the point (0.5, 0)
I know you still got an answer to your question but in future it might be better to post maths-related questions in the maths forum here

Cheers.

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Updated: December 8, 2010
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