integration under curve help Watch
- Thread Starter
Last edited by sam2109; 03-01-2011 at 23:19.
- 08-12-2010 23:58
- 09-12-2010 18:40
I didn't compute the integral, but looking at it, the curve is a minimum one with roots at x=1 and x=6, which means function is negative in that interval. So your integral should be negative, but as the answer is asking for the area, take the absolute value, i.e. 20.83. Also it may be preferable to give you answer as a fraction: 20,5/6