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1. A curve has equation y= (+2x-2)
Show that = (-3x-)

How do you do this? I differentiated the and got and the differentiated the bracket bit to get (2x+2) :/
2. (Original post by Nkhan)

A curve has equation: (+2x-2)
Show that = (5-3x-)

Well have you tried using the product rule?

(u x dv/dx) + (v x du/dx)

where u = the first part of your function and v = the second part of the function
3. (Original post by Mr_Muffin_Man)
Well have you tried using the product rule?

(u x dv/dx) + (v x du/dx)

where u = the first part of your function and v = the second part of the function
I differentiated the and got and the differentiated the bracket bit to get (2x+2) :/
4. (Original post by Nkhan)
I differentiated the and got and the differentiated the bracket bit to get (2x+2) :/
Your function is product of an exponential and a polinomial function,
let u=f(x) and v=g(x) so y=f(x)*g(x)
Derivating y (dy/dx)you should use the product rule for these type of functions.
This rule: Y' =f'(x)*g(x) + f(x)*g'(x)
5. As others have said, product rule that shizzle.
6. Seriously? Apply the Product Rule!!!

7. Hope that helps!q
8. See more solved problems on product rule at http://www.math24.net/derivative-of-...-quotient.html.
9. (Original post by Nkhan)
A curve has equation y= (+2x-2)
Show that = (-3x-)

How do you do this? I differentiated the and got and the differentiated the bracket bit to get (2x+2) :/
product rule: dy/dx of uv = v(du/dx) + u(dv/dx)

uv = [e^(-4x)] (x^2+2x-2)

therefore u = [e^(-4x)] and v = (x^2 + 2x - 2)
du/dx = -4e^(-4x) and dv/dx = 2x + 2

using that formula:

(x^2 + 2x - 2)[-4e^(-4x)] + [e^(-4x)](2x+2)

simplifying will hopefully give you the 'show that' answer

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Updated: December 10, 2010
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