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1. A curve has equation y= (+2x-2)
Show that = (-3x-)

How do you do this? I differentiated the and got and the differentiated the bracket bit to get (2x+2) :/
2. Use product rule mate. dy/dx = uv' + vu'
3. (Original post by Nkhan)
A curve has equation y= (+2x-2)
Show that = (-3x-)

How do you do this? I differentiated the and got and the differentiated the bracket bit to get (2x+2) :/
Then you would use the product rule and you have to do some simplifying down
4. (Original post by cpdavis)
Then you would use the product rule and you have to do some simplifying down
product rule on what bit? the x^2 +2x - 2 bit? i dont get it :|
5. (Original post by Nkhan)
product rule on what bit? the x^2 +2x - 2 bit? i dont get it :|
So for each term, when you differentiate them you should get -4e^-4x and 2x+2. So what you do is you times each differential with the alternative original product. This video might make it clearer

6. product rule

v = e^-4x

u = (x^2 +2x -2 )

dy/dx = vu' + uv'

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Updated: December 10, 2010
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