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# tan(pi/6+0.5arctan(3/4)? Watch

1. How on earth do I calculate it in exact form??
2. (Original post by XShmalX)
How on earth do I calculate it in exact form??
Use the formula for tan(A+B) and remember tan and arctan are inverse functions (subject to appropriate domain/codomain)
3. Expand using the double angle formulae, tan(arctan(3/4)) simplifies to 3/4 and tan(pi/6) is 1/3sqrt3
4. (Original post by ghostwalker)
Use the formula for tan(A+B) and remember tan and arctan are inverse functions (subject to appropriate domain/codomain)
Yeah, I tried that but got kinda stuck on what to do with the 1/2...
5. 1/2 is a constant.
6. (Original post by XShmalX)
Yeah, I tried that but got kinda stuck on what to do with the 1/2...
Note that , therefore:

In our case, so plugging this in to the above expression we get:

.

Rearrange this to be a quadratic in terms of and solve it (remember to get rid of the solution which doesn't make sense). Then follow your method to finish off the problem.
7. (Original post by boromir9111)
1/2 is a constant.
I don't think this helps, Boromir?
8. Actually, yeah it doesn't help! sorry about that OP.

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