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    Could some help me solve the following system please?

    1. 2P
    2. 3Q
    3. 4(1-P-Q)

    Thanks a lot.

    Edit: Could I set them as 2P=3Q=4(1-P-Q) obtain 6P-3Q=4 and then set that against 4(1-P-Q) and solve as a system of two equations?
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    Those aren't equations
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    (Original post by Hopple)
    Those aren't equations
    Thanks for your reply. I thought someone may say that. Normally the technique I'm using churns out answers like 2P+(1-P)and 3P. I set them equal and solve for P. This is what it's turned out this time. I suppose I'm asking how to solve three equations in two unknowns? Thanks again, could you offer any further insight?
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    Perhaps my ignorance shining through but what are you trying to find exactly? Values for P and Q which satisfy...?

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    If 2P = 3Q = 4(1-P-Q), you can surely find values which satisfy the equation like any other simultaneous equations.

    For example:
    2P = 4(1-P-Q)
    2P = 3Q
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    Well, if 2P=3Q, then using 2 and 3 gives 4-6Q-4Q=3Q, so Q is 4/13. That's if you're trying to find P and Q so that 1,2 and 3 are equal.
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    (Original post by Hopple)
    4-6Q-4Q=3Q, so Q is 13/4.

    Bad hair day?
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    Whoops, hopefully the OP got their answer though.
 
 
 
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