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1. The events A and B are such that probability of A=1/2 probability of B=1/3 and P(A ?B)=1/4.

Find...
b) P(AUB)
c) P(A/B’)

For b) I got 7/12
and c) 3/8

Thank you! (:
2. (Original post by Lilianna_Brooke)
The events A and B are such that probability of A=1/2 probability of B=1/3 and P(A ?B)=1/4.
I presume the "?" is "intersect"

Find...
b) P(AUB)
c) P(A/B’)

For b) I got 7/12
and c) 3/8

Thank you! (:
Agree with b).

If you meant the conditonal probability of A given B' for c), then yes, I agree with it.
It's usual to use a vertical line "|" for conditional probability.
If you meant anything else, you'll have to clarify.
3. I get the same results as you though I did it in my head which is never good practice in this type of probability and I have made the same assumptions as the previous poster.

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Updated: December 12, 2010
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