core ln question

why is 2ln4-2ln2=ln4

i know its ln16/ln4.

but how does ln/16 = ln4

you cant simply devide 16/4 normally as ln10/ln2 does not = ln5

a. ln(b) = ln(b^a)

ln(a) + ln(b) = ln (a.b)

ln(a) - ln(b) = ln (\frac{a}{b})

why is 2ln4-2ln2=ln4

i know its ln16/ln4.

but how does ln/16 = ln4

you cant simply devide 16/4 normally as ln10/ln2 does not = ln5

[br]2\ln4 - 2\ln2[br]= 2(\ln4 - \ln2)[br]= 2(\ln(\frac{4}{2})[br]= 2(\ln2)[br]= \ln2^2[br]= \ln4[br][br]

why is 2ln4-2ln2=ln4

i know its ln16/ln4.

but how does ln/16 = ln4

you cant simply devide 16/4 normally as ln10/ln2 does not = ln5

You're getting the rules mixed up. (See Spungo's post above ^^^)

2ln(4) - 2ln(2)
= ln(4^2) - ln(2^2)
= ln(16) - ln(4)
= ln(16/4)
= ln(4)

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