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    An explosive charge of mass 150g is designed to split into two parts, one with mass 100g and the other with mass 50g. When the charge is moving at 4m/s it splits and the larger part continues to move in the same direction whilst the smaller part moves in the opposite direction. Given that the speed of the larger part is twice the speed of the smaller part, find the speeds of the two parts.


    I'm nomrally quite good at collusion question, however with the particles exploding i do not know how to start off. any help would be much appreciated
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    And there was me thinking there was a pile up on the M1.
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    Give me a few minutes.
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    (Original post by Byrney11)
    An explosive charge of mass 150g is designed to split into two parts, one with mass 100g and the other with mass 50g. When the charge is moving at 4m/s it splits and the larger part continues to move in the same direction whilst the smaller part moves in the opposite direction. Given that the speed of the larger part is twice the speed of the smaller part, find the speeds of the two parts.


    I'm nomrally quite good at collusion question, however with the particles exploding i do not know how to start off. any help would be much appreciated
    Using conservation of momentum :

    Initial momentum = final momentum

    Hence, 0.15*4 = 0.1*2*v - 0.05v

    solving for v we get : v= 4

    smaller part's speed = 4

    larger part's speed = 8
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    aaaaahh i see what you have done, you put the inital charge as a particle as well. thats made things a lot clearer cheers
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    (Original post by Byrney11)
    aaaaahh i see what you have done, you put the inital charge as a particle as well. thats made things a lot clearer cheers
    I prefer drawing diagrams.... it makes things easier and if you mess up the actual calculation the examiner knows what you were intending to do so you may get some marks.

    Answering M1 in Jan ?
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    yeah im doing m1 c1 and c2 in january as i mucked up them quite badly in june
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    (Original post by Huskaris)
    And there was me thinking there was a pile up on the M1.
    haha me too
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    Just use conservation law of energy for momentums: m1u1+m2u2=m1v1+m2v2
    remembering to work in kilograms and changing direction means the velocity becomes negative
 
 
 
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