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For the life of me I can't work out this maths problem! Can you? Watch

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    I found this question in an old maths book under the Simultaneous Equations section. The question isn't exactly that difficult either, I have done other similar ones numerous times correctly but I'm not sure where to begin with this one.

    Here it is:

    Mariko has ten more sweets than Brian. If she gives him a quarter of her sweets, he will have six more than her.

    Find the number of sweets each child has.


    The answer:
    Spoiler:
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    Mariko 32 sweets; Brian 22 sweets


    The answer is in the spoiler but I would really appreciate it if someone could list step by step how they go about doing this, whether by elimination or substitution.
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    Mariko has ten more sweets than Brian. If she gives him a quarter of her sweets, he will have six more than her.

    Find the number of sweets each child has.

    Say Mariko's number of sweets is M, and Brian's is B.
    0.75M = 0.25M + B + 6
    0.5M = B + 6
    M = 2B + 12

    And it was told at the beginning M = B + 10

    B - 10 = 2B + 12
    B = 22

    And as M = B + 10, M = 32
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    (Original post by Jesse_Mac)
    Mariko has ten more sweets than Brian. If she gives him a quarter of her sweets, he will have six more than her.

    Find the number of sweets each child has.

    Say Mariko's number of sweets is M, and Brian's is B.
    0.75M = 0.25M + B + 6
    0.5M = B + 6
    M = 2B + 12

    And it was told at the beginning M = B + 10

    B - 10 = 2B + 12
    B = 22

    And as M = B + 10, M = 32
    Ahh what a relief, thanks!
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    (Original post by Final Fantasy)
    Ahh what a relief, thanks!
    You're welcome
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    Why don't you check with your maths teacher I struggled as well.
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    [QUOTE=Jesse_Mac;28936503]Mariko has ten more sweets than Brian. If she gives him a quarter of her sweets, he will have six more than her.

    Find the number of sweets each child has.

    Say Mariko's number of sweets is M, and Brian's is B.
    0.75M = 0.25M + B + 6
    0.5M = B + 6
    M = 2B + 12

    And it was told at the beginning M = B + 10

    B - 10 = 2B + 12
    B = 22

    And as M = B + 10, M = 32[That was ingenious I wish I figured that out. Do you do a-level maths?]
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    [QUOTE=duibb;28936997]
    (Original post by Jesse_Mac)
    Mariko has ten more sweets than Brian. If she gives him a quarter of her sweets, he will have six more than her.

    Find the number of sweets each child has.

    Say Mariko's number of sweets is M, and Brian's is B.
    0.75M = 0.25M + B + 6
    0.5M = B + 6
    M = 2B + 12

    And it was told at the beginning M = B + 10

    B - 10 = 2B + 12
    B = 22

    And as M = B + 10, M = 32[That was ingenious I wish I figured that out. Do you do a-level maths?]
    Aw, thanks. I did do A-Level maths, got an A* in it, but this isn't really stuff we did at A-Level, more just general problem-solving, arithmetic stuff. I'm usually the one asking questions here :P
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    (Original post by duibb)
    Why don't you check with your maths teacher I struggled as well.
    I don't have a maths teacher, I finished A-Level Maths a couple of years ago and haven't done much of it since, but now I'm at a point in my degree where I need to revisit it, which I have been doing for a couple of weeks now. Re-took the A-Level standard tests last week and achieved 91% - so I'm doing something right but it's going to get a lot harder soon after Christmas break is over.
 
 
 
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