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# Geometric sequence help ( c2 ) Watch

1. Yeah so I have this question

First 3 terms of a geometric series are ( 3q +1) , (2q+2) , (2q-1) respectively, where q is a non-zero constant.

how do i find the values of Q ? one is 5

i was thinking because its a geometric sequence divide a term by its previous term and do simultaneos equation.

2q+2 2q-1
------ = -------
3q+1 2q+2

But that didnt seem to work i got weird numbers like 3.4.23425.. etc when i know one of the values for Q is 5?

can anyone help me out please ? thanks =]
2. Your method is correct, but you have written 3q-1 instead of 3q+1 in your fraction. I presume if you change this, you will be able to find the correct answer...
3. (Original post by Scott3142)
Your method is correct, but you have written 3q-1 instead of 3q+1 in your fraction. I presume if you change this, you will be able to find the correct answer...
woops, ignore my typo , I used the correct sign when i did the working on the paper, but i got strange answers, would you be able to write out the workings step by step?
4. Let a be the first term, r the common difference.

5. ahaaa isee the error i made, thanks for your help =]

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