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1. You have r(1+sin) = a Find the cartesian form?

r + rsin = a
Where r is the square root of x^2 + y^2
and rsin is y.

I was fine until it realised it equalled to a what does a mean?

Thanks
2. It's just a constant.
3. Can't have sin without an argument or it's meaningless...
4. ...
5. Sorry r(1+sin(theta)) = a
Better?

So if is just a constant
squareroot(x^2+ y^2) + y = a
6. (Original post by Jowhar)
Sorry r(1+sin(theta)) = a
Better?

So if is just a constant
squareroot(x^2+ y^2) + y = a
What you've done is right but I suppose it would be better to simplify it:

...

as it's easier to see that what you have is just a quadratic.

edit: HTH. What part don't you get?
7. No im ok thank you now its just because i didnt know what to do with a as it was a 'constant' and im thinking whats a constant do i just leave it in there but now its ok
Thanks!

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