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# Help on question please :) Watch

1. Question: The curve C has equation y= 2x^2 - 10x + 16. The point P has coordinated (3, 4) and lies on C. Find equation of the tangent to C at P.

Any help would be grateful thanks
2. Find derivative and substitute x.

dy/dx = 4x-10
= 12 -10 = 2

Find equation for tangent. Use gradient, substitute in points of P to find y-intercept.

y = 2x + C
4 = 6 + C
C= 6 - 4 = -2

y = 2x - 2

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