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# HElp with surds (C1) Watch

1. Simplify, 6 root 2 MUTIPLY 5 root 3 MINUS root 24

Please could somebody help me answer this question. I'm finding difficulty in getting the right answer and would appreciate help from you guys

Thanks
2. Well , and . How might this help you? [Hint: can you see any square numbers?]
3. (Original post by nuodai)
Well , and . How might this help you? [Hint: can you see any square numbers?]
Yes, thanks, would root 24 become 2 root 3 root 2 ?

If that's right, what do i do now plz?? (If wrong, where have i gone wrong :P)

I multiplied the first two bits to get 30+ 6 root 3 + 5 root 2 +root 6 - 2 root 2 root 3

Is that even right?
btw i really appreciate your help
4. (Original post by TheWonderKid)
Yes, thanks, would root 24 become 2 root 3 root 2 ?

If that's right, what do i do now plz?? (If wrong, where have i gone wrong :P)

I multiplied the first two bits to get 30+ 6 root 3 + 5 root 2 +root 6 - 2 root 2 root 3

Is that even right?
btw i really appreciate your help
I think you've stuck in some + signs where they're not supposed to be (either that or you missed some out in your first post).

You have .

You've worked out (correctly) that .

Also note that the general rule is that . So how might you simplify it? [Hint: look for common factors.]

Also it's usually neater to write instead of .
5. Ahh GOT IT!

6\sqrt{2} \times 5\sqrt{3} = 30\sqrt{6}

And then you take 2 \sqrt{6} away from this which gives you 28\sqrt{6} which is the final answer?

Is that right?

Thankyou ever so much for your help
6. (Original post by TheWonderKid)
Ahh GOT IT!

6\sqrt{2} \times 5\sqrt{3} = 30\sqrt{6}

And then you take 2 \sqrt{6} away from this which gives you 28\sqrt{6} which is the final answer?

Is that right?

Thankyou ever so much for your help
That's right No problem.

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