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    Hey,
    Please can someone help me with this question..it's from JUNE 2008 EDEXEL CORE 3

    f(x) = 1 / x + 1 x>3

    find the range of f?

    I have looked at the mark scheme but really don't understand the answer

    please can someone help?

    Thankyou
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    is that f(x)=\dfrac{1}{x+1} with x>3 ?

    if so, what happens to f(x) as x increases?
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    The range of a function is the values which f(x) can assume on the y-axis (i.e. the highest and lowest values a function can have).

    if f(x) = \dfrac{1}{x} + 1 and x > 3, what happens to the value of f(x) as x gets larger and larger?
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    The domain of the function is that x>3, and an element of the real numbers, presumably.

    The function's range of outputs in this case is at between 1/4, since 1/ 3 + 1 = 1/4, and 0, since 1/ <><> + 1 is roughly zero.

    Therefore 0 < f < 1/4.

    Note the inequality's strictness - f can never be quite 1/4 since x can never be quite 3, and f can never quite be zero since so number has the property of having a reciprocal of zero - at least, any properly defined number.
 
 
 
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