What does it mean by delta H = 0.
a change in temperature will not affect the equilibrium position when delta H = 0.
Does that mean if the temperature of the forward and reverse reaction is the same then temperature doesn't effect the equilibrium position?
Delta H = O effect on equilibrium position of temperature. meaning? Watch
- Thread Starter
- 19-12-2010 11:12
- 19-12-2010 11:27
Delta H of the froward reaction is zero therefore the reaction isn't driven by either a positive or negative enthalpy change.
So temperature will not have an effect on the Equilibrium position.
I think you are confused about the effect of temperature on the position of EQUILIBRIUM.
Here is an example to illustrate the point.
If the Delta H (enthalpy change) for a reaction is +567 Kj per mole. Temperature does have an effect on a reaction like this e.g if you increase temp reaction moves to endothermic side to absorb extra heat so equilibrium position moves to the right, and if you decrease temp the opposite occurs.
However if the Delta H = 0 for a reaction then temperature has no effect on the position of equilibrium because it effects both the forward and backward reaction identically i.e. at same rate (like a catalyst, temperature in this reaction has no effect on the yield of equilibrium)
I hope that helped.
Just think about the statement and ask yourself why until you see the light at the end of the tunnel.
- Thread Starter
- 19-12-2010 11:35
Got it,so theres no temp which is exo or endo, and we know if temp is positive it favours endo, and if temp is negative favours exo, here temp = o so it doesnt effect equilibrium position as it doesnt favour any reactions.