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    So my a2 book says to get from a halogenoalkane to an alcohol, you add NaOH/H2O reflux.

    I'm just wondering what the bi-product would be?

    Looking back at the AS book...

    If CH3CH2CH2CH2Cl + H20 ---> CH3CH2CH2CH2OH + H+ + Cl-
    Then Ag+ + Cl- forms AgCl

    (hydrolysis) So I'm kinda stuck :/

    Any help will be much appreciated
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    (Original post by tripodd)
    So my a2 book says to get from a halogenoalkane to an alcohol, you add NaOH/H2O reflux.

    I'm just wondering what the bi-product would be?

    Looking back at the AS book...

    If CH3CH2CH2CH2Cl + H20 ---> CH3CH2CH2CH2OH + H+ + Cl-
    Then Ag+ + Cl- forms AgCl

    (hydrolysis) So I'm kinda stuck :/

    Any help will be much appreciated
    The Ag+ comes from you using silver nitrate to identify the presence of a halide ion. So you will have a nitrate group floating around, meaning the proton will react with that, giving HNO3.

    Without AgNO3, you'd just get HCl from the nucleophilic substitution.
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    Mainly HCL along with (water and traces of haloalkane)[minutely]
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    Thanks for the help guys :]

    Would I be right to say then...
    CH3CH2CH2CH2Cl + NaOH ---> CH3CH2CH2CH2OH + NaCl?
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    (Original post by tripodd)
    Thanks for the help guys :]

    Would I be right to say then...
    CH3CH2CH2CH2Cl + NaOH ---> CH3CH2CH2CH2OH + NaCl?
    Yes- and ........the actually by -product turns out to be Nacl.On adding AgNO_3 to it would give AgCl + NaNO_3.
 
 
 
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