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    Okay so I was working through this paper and was doing fine until I marked my answer in question 5b, apparently the examiners think its meant to be
    ( X - 15cos30 = Rcos50) instead of (Rcos50 + X - 15cos30 = 0).

    Can any kind soul please please tell me that I resolved the forces correctly, I am on so much pressure cracking my brain here to figure out why they think its the first one.

    thankyou
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    Rcos50 is the resultant force of P and Q. So if you take Q going to the right and minus P going to the left you get the resultant force.

    Don't think of R as another force going to the right that is acting with the other forces going to the right that must be balanced out with the left: it is the resultant force.

    In class we did this a different way though:

    You can form a triangle OQR and use sine rule to find both R and X.
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    (Original post by Thrug)
    Rcos50 is the resultant force of P and Q. So if you take Q going to the right and minus P going to the left you get the resultant force.

    Don't think of R as another force going to the right that is acting with the other forces going to the right that must be balanced out with the left: it is the resultant force.

    In class we did this a different way though:

    You can form a triangle OQR and use sine rule to find both R and X.
    Dang!, should've have stayed on this. Sorry for late reply, I kinda gave hope anyone was going to bother just getting out of bed to resolve mechanics.
    So in essence, Q - P = R then. Makes perfect sense. I thought of the triangular method but seems to me I prefer this one.
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    (Original post by mauvetard)
    Dang!, should've have stayed on this. Sorry for late reply, I kinda gave hope anyone was going to bother just getting out of bed to resolve mechanics.
    So in essence, Q - P = R then. Makes perfect sense. I thought of the triangular method but seems to me I prefer this one.
    Yea that's the first time I've seen the forces resolved into a triangle so I'd just stick to resolving how I normally do it.

    And yes, as always R is the combination of the other forces:

    R = Q + P. But as Q and P are in opposite directions, it's kinda like Q + -P = R.
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    (Original post by Thrug)
    Yea that's the first time I've seen the forces resolved into a triangle so I'd just stick to resolving how I normally do it.

    And yes, as always R is the combination of the other forces:

    R = Q + P. But as Q and P are in opposite directions, it's kinda like Q + -P = R.
    Agreed!. Now Im sure as to not make a stupid mistake in the exam, wouldn't want to meddle with too many methods .Thanks for clarification!.
 
 
 
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