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    I'm not sure on how to do this question. If there is 20m to form the three sides, the sides on the left and right would be 20 - x ? The bottom could then be 20-x doubled ?
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    :lolwut: are you sure this is C1?
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    Well, for this rectangle, 3 of the sides are bound by the rope, which has a length of 20m. We know that two of the lengths are x, so the third length must be clearly 20-2x. Length times width gets you x*(20-2x) which is the area and the answer that you have to show.

    You have to remember, the fourth side is bound by the wall, so we don't need to worry about that in our calculations.


    (Original post by ilyking)
    :lolwut: are you sure this is C1?
    It's C1 on some exams boards, but C2 in other boards/
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    If you've got 20 m and you've got two sides that are x metres, the length left over is 20-2x metres
    so the area is x(20-2x)=20x-2x^2
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    Oh didn't think of it like that , thanks everyone
 
 
 
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