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    The curve y = 5rootx is transformed by a stretch, scale factor 1/2, parallel to the x-axis. Find the equation of the curve after it has been transformed.

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    If it is stretched parallel to the x axis , it'll be x over c . So x over half, so x should be multiplied by 2 to get the denominator over 1?

    Is the answer 10root x ?
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    (Original post by Gelato)
    The curve y = 5rootx is transformed by a stretch, scale factor 1/2, parallel to the x-axis. Find the equation of the curve after it has been transformed.

    --------------------

    If it is stretched parallel to the x axis , it'll be x over c . So x over half, so x should be multiplied by 2 to get the denominator over 1?

    Is the answer 10root x ?
    Nope.

    That scales the y-axis by a factor of 2. You must apply the change to "x", exactly "x", not any function of x. Replace x itself with x/(1/2)
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    Ohh okay so ,

    It'd be y= 5root2x ?

    As x/1/2 , need to multiply the 1/2 by 2 to get 1 , so also multiply x by 2 ?

    Edit: Thanks , repped
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    (Original post by Gelato)
    Ohh okay so ,

    It'd be y= 5root2x ?

    As x/1/2 , need to multiply the 1/2 by 2 to get 1 , so also multiply x by 2 ?
    Yes. y=5\sqrt{2x}
 
 
 
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