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    A diver is 50M below the surface of the water

    The density of the water is 100 kg/m cubed and the acceleration of free fall is 10m/s squared.

    Pressure = dhg. Density x Gravitational field strength x Change in height

    Pressure = 1000x 10x50 = 500kPa

    The window in the driver's helmet is 150mm wide and 70mm from top to bottom.

    Calculate the force that the water on this window.

    Force =

    How do I work the second part out?


    Pa = force(N)/area m squared

    Do I rearrange the question to get force and turn the area from mm squared to m squared and times it to get force.

    500,000 PA x ((150x70)/1000000) = 5250 N?
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    Is this P2 yeah? We're just getting upto that after Jan
    I've got my P1 in January
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      (Original post by aliakhtar)
      A diver is 50M below the surface of the water

      The density of the water is 100 kg/m cubed and the acceleration of free fall is 10m/s squared.

      Pressure = dhg. Density x Gravitational field strength x Change in height

      Pressure = 1000x 10x50 = 500kPa

      The window in the driver's helmet is 150mm wide and 70mm from top to bottom.

      Calculate the force that the water on this window.

      Force =

      How do I work the second part out?

      Pa = force(N)/area m squared

      Do I rearrange the question to get force and turn the area from mm squared to m squared and times it to get force.

      500,000 PA x ((150x70)/1000000) = 5250 N?
      So the pressure in a stable fluid like this is the same everywhere and acts equally in all directions.

      So, you're right.
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      Convert the dimensions to metres, then rearrange the equation for force and substitute your values in. Your final answer will be in newtons so long as you use Pascals for the pressure, and metres squared for the area.
     
     
     
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