Let's see who's got the brain to solve this problem.
Calculus Challenge Watch
- Thread Starter
- 21-12-2010 21:15
- 21-12-2010 22:06
And can be solved with series of substitution
a=x+2 and dx=da
b=Va ->a=b^2 ->da=2b db so
-> b=c^2-2 ->db=2c dc
and continue with similar substitution up to there is not sqare root.
You will for example substituting n-times (n square root) and at last with z
Then multplying the powers integrate by terms and resubstitute.
It means long and systematic work.
For an example:
http://www.wolframalpha.com/input/?i...29%29%29%29+dxLast edited by ztibor; 21-12-2010 at 22:42.
- 21-12-2010 23:55
- 22-12-2010 02:45
see if you can get an ODE out of that by differentiating and squaring