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    Hi tsr,

    I need help with this c1 question.

    Sorry i don't know how to post pictures so the link is :

    https://eiewebvip.edexcel.org.uk/Rep...e_20060622.pdf

    Question 11 (d).

    I get area of triangle as 1/2*base*height, but i don't understand how they get the height. Length PQ is 6 root 5, but they use RS (3root5) as the height. Why did they use RS? It asks for area of PQR?

    thanks
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    (Original post by Extricated)
    Hi tsr,

    I need help with this c1 question.

    Sorry i don't know how to post pictures so the link is :

    https://eiewebvip.edexcel.org.uk/Rep...e_20060622.pdf

    Question 11 (d).

    I get area of triangle as 1/2*base*height, but i don't understand how they get the height. Length PQ is 6 root 5, but they use RS (3root5) as the height. Why did they use RS? It asks for area of PQR?

    thanks
    i remember doing this question a few weeks ago when revising.

    My first piece of advice would be to sketch the points onto a graph and draw the triangle out.

    Once you've done this you'll see that RS (i think) is the perpendicular height so using area= 1/2 base x height with base as PQ and height as RS the answer you should get is 45

    PS doing this from the top of my head and my memory isn't so good either , i might be wrong
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    If you've worked out SR as 3rt5, this is the height of the triangle as SR is perpendicular to PQ (as SR is on l2 and PQ is on l1)

    Draw a diagram - this should help
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    (Original post by Extricated)
    Hi tsr,

    I need help with this c1 question.

    Sorry i don't know how to post pictures so the link is :

    https://eiewebvip.edexcel.org.uk/Rep...e_20060622.pdf

    Question 11 (d).

    I get area of triangle as 1/2*base*height, but i don't understand how they get the height. Length PQ is 6 root 5, but they use RS (3root5) as the height. Why did they use RS? It asks for area of PQR?

    thanks
    I've just drawn it now.

    You really need to sketch it first in order to see what's going on.

    Line 2, going from the x axis to where it intersects with line 1 is RS and hence the height of the triangle.

    Remember that line 2 is perpendicular to line 1 so you know what you need to do having first found PQ( the base of the triangle).
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    (Original post by sohail.s)
    i remember doing this question a few weeks ago when revising.

    My first piece of advice would be to sketch the points onto a graph and draw the triangle out.

    Once you've done this you'll see that RS (i think) is the perpendicular height so using area= 1/2 base x height with base as PQ and height as RS the answer you should get is 45

    PS doing this from the top of my head and my memory isn't so good either , i might be wrong
    Correction : Your memory is very good!

    Thank you for the answer, i now see that RS is the perpendicular height, it's just that all other papers with area of triangle questions are different to that.
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    (Original post by Extricated)
    Hi tsr,

    I need help with this c1 question.

    Sorry i don't know how to post pictures so the link is :

    https://eiewebvip.edexcel.org.uk/Rep...e_20060622.pdf

    Question 11 (d).

    I get area of triangle as 1/2*base*height, but i don't understand how they get the height. Length PQ is 6 root 5, but they use RS (3root5) as the height. Why did they use RS? It asks for area of PQR?

    thanks
    RIP.....wud appreciate if such nooby questions werent asked on tsr ffs
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    (Original post by Rahul.S)
    RIP.....wud appreciate if such nooby questions werent asked on tsr ffs
    Stop hunting for negative rep on a Maths Help forum, or refrain from being so ridiculous please.
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    (Original post by Chelle-belle)
    Stop hunting for negative rep on a Maths Help forum, or refrain from being so ridiculous please.
    first i no extricated...second its nt quoted from u.....RIP YH........C1=100

    RIP CHELLE-BELLW
 
 
 
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