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    Use the product rule to differentiate xtanx

    The answer in the book says tanx+xsex^2x

    Does it matter if you write xsec^2x + tanx though?
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    (Original post by Nkhan)
    Use the product rule to differentiate xtanx

    The answer in the book says tanx+xsex^2x

    Does it matter if you write xsec^2x + tanx though?
    Mate ur doing a-level and i cant believe that you dont seem to know that it is the same thing. They are commutative :  A+B = B+A
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    hahahahahahhahaha but no it doesnt matter
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    No. According to the commutative law a+b=b+a, so both those expressions are identical. All you've done is swapped u and v in this:

    \frac{d}{dx}(uv) = \frac{du}{dx}v + u\frac{dv}{dx}
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    (Original post by wizz_kid)
    Mate ur doing a-level and i cant believe that you dont seem to know that it is the same thing. They are commutative :  A+B = B+A
    Lool ayy low me :|
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    (Original post by Nkhan)
    Use the product rule to differentiate xtanx

    The answer in the book says tanx+xsex^2x

    Does it matter if you write xsec^2x + tanx though?
    I'm wondering why the book has made a 'sex' function
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    Easy

    Edit:... yeh so I kind of jumped to conclusion, thinking you didn't know how to solve it, and didn't read your thread properly. The order doesn't matter since they are both positive values.... you really should know by this stage of maths already....
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    (Original post by dnumberwang)
    I'm wondering why the book has made a 'sex' function
    Lool sorry about that, my typo error I guess :/
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    (Original post by APonderingMind)
    Easy

    Edit:... yeh so I kind of jumped to conclusion, thinking you didn't know how to solve it, and didn't read your thread properly. The order doesn't matter since they are both positive values.... you really should know by this stage of maths already....
    :K:

    Are you sure that is the reason why.



    (Original post by Nkhan)
    Lool sorry about that, my typo error I guess :/
    Don't worry about people like that. But it's nevertheless important that you know how to check and have confidence in your own answers.
    Easy way to check if your answer is the same is by putting in numbers. Essentially xsec^2x + tanx are going to be just numbers. Does 5+6=6+5? Yep. So you have every right to be confident that you can write (xsec^2x + tanx) or (tanx + xsec^2x) as your answer, because they are the same. As long as you get the right answer and you do what they ask you to do, they will allow different forms of the same answer like you have given.
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    (Original post by APonderingMind)
    The order doesn't matter since they are both positive values
    You can say something stronger than that...
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    (Original post by dnumberwang)
    I'm wondering why the book has made a 'sex' function
    Darn....you beat me to it
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    (Original post by Chelle-belle)
    :K:

    Are you sure that is the reason why.
    ...why exactly are we having a debate over something as simple as this? It's actually insulting my intelligence. =/

    You tell me then, is 4+2 the same as 2+4? Is 2-4, the same as 4-2?

    Jeez, what a way to waste time.
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    (Original post by IrrationalNumber)
    You can say something stronger than that...
    I could, but if the OP doesn't even understand the basic rules of maths, should I dwell into it any further?

    If it makes you happy:

    A + B = B + A

    A - B = -B + A

    B - A = -A + B
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    (Original post by APonderingMind)
    ...why exactly are we having a debate over something as simple as this? It's actually insulting my intelligence. =/

    You tell me then, is 4+2 the same as 2+4? Is 2-4, the same as 4-2?

    Jeez, what a way to waste time.
    trick question????????

    yes and no
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    (Original post by APonderingMind)
    I could, but if the OP doesn't even understand the basic rules of maths, should I dwell into it any further?

    If it makes you happy:

    A + B = B + A

    A - B = -B + A

    B - A = -A + B
    It's the fact that you mention them being positive values that bothers me. The fact that they are positive has no bearing on them being commutative under addition or not. In fact, tan isn't everywhere positive and neither is xsec^2x.
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    (Original post by APonderingMind)
    It's actually insulting my intelligence. =/
    Sorry, I didn't mean to insult your intelligence. My issue is the same as the one above, and my post was to make you think about what was off about your reason. And it's not (or was not) really a debate (yet).
 
 
 
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