C1 Integration Question

Original post by joeh37

sub in x=1 and set y = 7

This, and then solve for C.

Reply 3

joeh37

Original post by im so academic

This, and then solve for C.

That was implied :tongue:

Reply 4

OP

Original post by im so academic

This, and then solve for C.

7 = \frac {1}{3}x^3 + 2x^2 + 4x + c

So would that be:

7 = \frac {1}{3} + 2 + 4 + c

Right?

But how would c =

\frac {2}{3}

?

(edited 13 years ago)

Reply 5

Original post by Mr Inquisitive

7 = {1}{3}x^3 = 2x^2

So would that be:

7 = 1 + 1 + 4 + c

Right?

But how would c =

\frac {2}{3}

?

y = 1/3 + 2 + 4 + c

7 = 19/3 + c

Then rearrange to find c. (which is 2/3).

Substitute the value for c in f(x) to get the equation.

Reply 6

OP

Original post by im so academic

y = 1/3 + 2 + 4 + c

7 = 19/3 + c

Then rearrange to find c.

Ahh, thank you. :smile:

Reply 7

Original post by Mr Inquisitive

Ahh, thank you. :smile:

Remember though that is not the answer as the question specifically states to write down the equation.

Reply 8

M Loy is God

7

Hi GUYS IM MR INQUISITIVE AND

1 TIMES 2 = ...

... 1!!!???

What the ****.

Reply 9

OP

Original post by im so academic

Remember though that is not the answer as the question specifically states to write down the equation.

Just the

y = \frac{1}{3}x^3 + 2x^2 + 4x + \frac {2}{3}

then?

Reply 10

Original post by Mr Inquisitive

Just the

y = \frac{1}{3}x^3 + 2x^2 + 4x + \frac {2}{3}

then?

Reply 11

Original post by M Loy is God

Hi GUYS IM MR INQUISITIVE AND

1 TIMES 2 = ...

... 1!!!???

What the ****.

Lol this.

Reply 12

OP