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    How would you differentiate this: http://img28.imageshack.us/img28/3083/diffo.png

    What methods are there and which is best suited to this?

    Thank you!
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    Chain rule, let u = (x+1)/2
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    The derivative of Ln(x) and the chain rule?
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    (Original post by themagicpiano)
    How would you differentiate this: http://img28.imageshack.us/img28/3083/diffo.png

    What methods are there and which is best suited to this?

    Thank you!
    Remember that  \frac{d(ln(f(x)}{dx}= \frac{f'(x)}{f(x)}
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    \displaystyle\frac{1}{3}ln(\frac  {x+1}{2})\equiv\frac{1}{3}ln(x+1  )-\frac{ln2}{3}
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    \frac{d}{dx}lnf(x)=\frac{f'(x)}{  f(x)}
    f(x)=\frac{1}{2}x+\frac{1}{2}, f'(x)=\frac{1}{2}
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    I give up, latex is too complicated for me.
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    (Original post by wizz_kid)
    Remember that  \frac{d}{dx} \ln(f(x)) = \frac{f'(x)}{f(x)}
    This (though now fixed :P ).

    Also, Ewan that sig is awesome lol.
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    (Original post by wizz_kid)
    Remember that  \frac{d(ln(f(x)}{dx}= \frac{f'(x)}{f(x)}
    (Original post by StephenNeill)
    This (though now fixed :P ).
    The only thing wrong with the original was a missing bracket. There's absolutely nothing wrong with writing \frac{d(x^2)}{dx} = 2x, for example.
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    (Original post by EEngWillow)
    The only thing wrong with the original was a missing bracket.
    Actually there are two brackets missing. And that's all I was correcting.
    I did not mean to imply the small cosmetic shift to suit my own aesthetic disposition was a mathetmatical "correction".
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    (Original post by StephenNeill)
    This (though now fixed :P ).

    Also, Ewan that sig is awesome lol.
    I love it when you talk dirty :sexface:
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    (Original post by StephenNeill)
    Actually there are two brackets missing. And that's all I was correcting.
    I did not mean to imply the small cosmetic shift to suit my own aesthetic disposition was a mathetmatical "correction".
    Ah sorry, my mistake! Feel like a bit of a **** now :P
 
 
 
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