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# Trigonometry rearrangement Watch

1. Something easy I shouldn't be struggling with but can't seem to do:

Use the substitution and and to show that

I can get as far as showing but then keep seeming to go around in circles.
2. what are A and B??
3. (Original post by barnisaurusrex)

Using those would finish off the question easily
4. (Original post by barnisaurusrex)
Didn't pass the step that you got to to arrive at the answer so if you show your steps, I can give you some guidance.

Alternatively, if you want to start it fresh, play with the idea
5. (Original post by Clarity Incognito)
Didn't pass the step that you got to to arrive at the answer so if you show your steps, I can give you some guidance.

Alternatively, if you want to start it fresh, play with the idea
Already tried that one, and the identities above. I'm trying to eliminate A and B here and everything I try gets rid of some A's and B's and adds a few more. Can you suggest an immediate step from the point I got to?

edit: hold on, how incredible retarded of me.

sigh. Knew it was something simple. Cheers CI.
6. (Original post by barnisaurusrex)
Already tried that one, and the identities above. I'm trying to eliminate A and B here and everything I try gets rid of some A's and B's and adds a few more. Can you suggest an immediate step from the point I got to?

7. (Original post by barnisaurusrex)
Already tried that one, and the identities above. I'm trying to eliminate A and B here and everything I try gets rid of some A's and B's and adds a few more. Can you suggest an immediate step from the point I got to?

edit: hold on, how incredible retarded of me.

sigh. Knew it was something simple. Cheers CI.
No worries
8. I don't suppose you also get also equalling do you? My equation would work out nicely if it did but I can't seem to show it yet again, if it does. I have a feeling it doesn't though.
9. (Original post by barnisaurusrex)
I don't suppose you also get also equalling do you? My equation would work out nicely if it did but I can't seem to show it yet again, if it does. I have a feeling it doesn't though.
If

then

implies that

of which no solutions exist therefore

and so what we wanted to show is the same as sin(k) is not true.

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