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1. Q1) Using algebraic division ONLY show that can be written in the form:

where a, b and r and integer constants.

Q2)

Find the value of k for which the equation:

has equal roots
2. (Original post by jsmith6131)
Q1) Using algebraic division ONLY show that can be written in the form:

where a, b and r and integer constants.

Q2)

Find the value of k for which the equation:

has equal roots

What do u need help with mate? U got any working?
3. (Original post by jsmith6131)
Q1) Using algebraic division ONLY show that can be written in the form:

where a, b and r and integer constants.

Q2)

Find the value of k for which the equation:

has equal roots
Do you know how to do algebraic long division? If so divide by and this will give you the values for a, b and r.

For the second question, use the discriminant of the quadratic formula.
4. O thanks, for Q2) I now got k = 4, -2 which is correct

for q1) when i divided by x-2 I got with a remainder of -x
5. this is why I am stuck
6. (Original post by jsmith6131)
Q1) Using algebraic division ONLY show that can be written in the form:

where a, b and r and integer constants.

Q2)

Find the value of k for which the equation:

has equal roots
i think i've done a similar if not the same question and in that a previous part told you what r the remainder was and then you had to use long division to get the other bit
7. (Original post by jsmith6131)
O thanks, for Q2) I now got k = 4, -2 which is correct

for q1) when i divided by x-2 I got with a remainder of -x
You haven't done the last step of the division. Remember that is the same as If you use this you should get an integer remainder after the division.
8. I'm assuming you're after how you'd do these.

Fpr the first one you need to divide the original polynomial by (x-2). This will give another polynomial (which will be a quadratic with no constant) and a remainder (which is r).

For the second one, you need to simplify the quadratic. Them you need to find a value which gives a discriminant of 0 (which is b^2-4ac)

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Updated: December 29, 2010
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