# So Expression? What did you think of todays exam?Watch

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#1
Hey, you were sitting like 3 chairs in front of me.

It was definitely a bit harder than the PAS151 paper. Got the paper with me and made a few silly mistakes, however it would seem I got enough to pass the module.

Hardest question for me which I didn't even bother with was A11

[A11]

Let a, b and w be constants.

Find f'(x), where f(x) = e^((-(x-a)^2)/b)*sin(wx)

Bugger that. Only worth 4 marks out of 90 as well.

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16 years ago
#2
(Original post by byb3)
Hey, you were sitting like 3 chairs in front of me.

It was definitely a bit harder than the PAS151 paper. Got the paper with me and made a few silly mistakes, however it would seem I got enough to pass the module.

Hardest question for me which I didn't even bother with was A11

[A11]

Let a, b and w be constants.

Find f'(x), where f(x) = e^((-(x-a)^2)/b)*sin(wx)

Bugger that. Only worth 4 marks out of 90 as well.

Ay up, yeah by far tougher than PAS151 - think it was a bit of a naff paper, he went a bit ln / e crazy, compared to the mock paper, but all the same I reckon I've done enough after I took the AiM test marks off the 40 needed overall.
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16 years ago
#3
(Original post by byb3)
Hey, you were sitting like 3 chairs in front of me.

And by the by - I didn't notice who was sat behind me, was probably busy filling my white slip in when you went past.
I knew one of the girls (MChem/Maths) that were somewhere behind as she waved as she went past to take her seat.

The one in front, of me I walked in with, she's on my course, and is the other one of my supposed "Girlfriends I'm too busy paying attention to..." (to coin a phrase!).
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#4
(Original post by Expression)
And by the by - I didn't notice who was sat behind me, was probably busy filling my white slip in when you went past.
I knew one of the girls (MChem/Maths) that were somewhere behind as she waved as she went past to take her seat.

The one in front, of me I walked in with, she's on my course, and is the other one of my supposed "Girlfriends I'm too busy paying attention to..." (to coin a phrase!).

I needed 31 marks on that paper, which I have easily got!

Partial fractions question was a bit of a teaser, took me more time than I would like to mention.

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16 years ago
#5
(Original post by byb3)
Notes the use of the word "youth", something you were questioning my use of in August, which means the S. Yorks parlance is starting to creep in, over the screech that was you recording of "Why-aye man" a little while back .

As for "the red head", Jenna, theres no 'love' going off, and one of the main reasons I'm seen around with her so much is that we share the same lectures, degree title, tutorials, and personal tutors.

(Original post by byb3)
I needed 31 marks on that paper, which I have easily got!

Partial fractions question was a bit of a teaser, took me more time than I would like to mention.

Partial fractions was a little nasty, but not unachievable, the Expo. Oscil'ns took a long time !

Needed 33.
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16 years ago
#6
Couldn't this have been done via PM?

I'll make it more Universal by asking - what the subject matter of the paper was.
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16 years ago
#7
(Original post by Bigcnee)
Couldn't this have been done via PM?

I'll make it more Universal by asking - what the subject matter of the paper was.
Todays, PMA101, was Pure Mathematics Core - a nasty mismash of P1, P2, P3, P4, P6 built on a little more.

PAS151 yesterday was a Stats unit, that was rather pleasent.
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#8
(Original post by Bigcnee)
Couldn't this have been done via PM?

I'll make it more Universal by asking - what the subject matter of the paper was.
Nah, I like to let the other maths geeks take a look. Which unfortunately you have now fell under Bigcnee The paper was on Pure Mathematics core. Here is a tester for you.

Find Int[(Sin(x))^2 * (Cos(x))^2]dx

Worth 7 marks that baby!
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16 years ago
#9
Where did you have the exam?
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#10
(Original post by viviki)
Where did you have the exam?
The Goodwin sports centre.

Either me memory is crap or I never knew you were at Sheffield Uni! wow..

So which year are you, and what do you do, what do you do?

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16 years ago
#11
MA Law I just wondered cos I had an exam in firth hall this morning and we had maths people in there.

That would be LAW6025: Constituational Law then.
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16 years ago
#12
(Original post by viviki)
MA Law I just wondered cos I had an exam in firth hall this morning and we had maths people in there.
Strange, nothing on the AMA (Applied), PMA (Pure) and PAS (Stats) timetables referring to any other Maths exams other than this mornings PMA101 at Goodwin, and its not as if we were short for spaces...
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16 years ago
#13
hehe yup thats the one. Well there were people in there looking at equations who had calculators so I presume they were maths.
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16 years ago
#14
(Original post by byb3)
Find Int[(Sin(x))^2 * (Cos(x))^2]dx
I was about to say how easy that was, until i noticed thats '*' not '+' !
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16 years ago
#15
(Original post by viviki)
Well there were people in there looking at equations who had calculators so I presume they were maths.
ACS6005: Signal Processing, Estimation and Image Processing
(ACS: Automatic Control & Systems Engineering).

Thats the exam you are referring to.
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16 years ago
#16
(Original post by byb3)
Nah, I like to let the other maths geeks take a look. Which unfortunately you have now fell under Bigcnee The paper was on Pure Mathematics core. Here is a tester for you.

Find Int[(Sin(x))^2 * (Cos(x))^2]dx

Worth 7 marks that baby!
Using cos (2x)=1-2sin^2(x)=2cos^2(x)+1
sin^2(x)=0.5(1-cos(2x)) and cos^2(x)=0.5(1+cos(2x))

So sin^2(x)cos^2(x)=0.25(1-cos2x)(1+cos2x)
=0.25(1-cos^2(2x))

Using cos^2(2x)=0.5(1+cos(4x))
sin^2(x)cos^2(x)=0.25(1-0.5(1+cos(4x))
=0.125(1-cos(4x))
Integrate it to get 0.125(x-0.25sin(4x))+c=x/8-sin(4x)/32+c

Nice little question really. (argh, it's like dangling a carrot in front of me. Damn geekyness.)
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#17
(Original post by meepmeep)
Using cos (2x)=1-2sin^2(x)=2cos^2(x)+1
sin^2(x)=0.5(1-cos(2x)) and cos^2(x)=0.5(1+cos(2x))

So sin^2(x)cos^2(x)=0.25(1-cos2x)(1+cos2x)
=0.25(1-cos^2(2x))

Using cos^2(2x)=0.5(1+cos(4x))
sin^2(x)cos^2(x)=0.25(1-0.5(1+cos(4x))
=0.125(1-cos(4x))
Integrate it to get 0.125(x-0.25sin(4x))+c=x/8-sin(4x)/32+c

Nice little question really. (argh, it's like dangling a carrot in front of me. Damn geekyness.)
Sounds about what I got. I remember the 1/8 and 1/32 towards the end. I did it slightly differently, but none the less, the same answer.
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16 years ago
#18
(Original post by byb3)
Let a, b and w be constants.

Find f'(x), where f(x) = e^((-(x-a)^2)/b)*sin(wx)
Chain rule one and product rule combined:
Let f(x)=g(x)h(x) where g(x)=e^((-(x-a)^2/b)

let u=-(x-a)^2/b=-(x^2-2ax+a^2)/b so y=e^u
=>du/dx=-(2x-2a)/b and dy/du=e^u

dy/dx=dy/du . du/dx = e^u . (2a-2x)/b
=((2a-2x)e^((-(x-a)^2)/b))/b

Product rule:
If f(x)=g(x)h(x), f'(x)=g'(x)h(x)+g(x)h'(x)
so f'(x)=(sin(wx)*(2a-2x)e^((-(x-a)^2)/b))/b+we^((-(x-a)^2/b)cos(wx)

a bit long for the marks though really.
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16 years ago
#19
(Original post by byb3)
Nah, I like to let the other maths geeks take a look. Which unfortunately you have now fell under Bigcnee The paper was on Pure Mathematics core. Here is a tester for you.

Find Int[(Sin(x))^2 * (Cos(x))^2]dx

Worth 7 marks that baby!
here is the maths paper we had to do: and . would you say it is easier or harder than your one?
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#20
(Original post by elpaw)
here is the maths paper we had to do: and . would you say it is easier or harder than your one?
Well I would assume that it was harder because it is taken at oxford. It also looks harder. There are some parts which don't seem familiar to me at all.

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