Expansion of ln(1+ sin x)

Expansion of ln(1+ sin x)

How do you do this?

So far I've got

ln ( 1 + x - x³/3! .....)

Expand the log first.

I don't get it.

Do you know how to expand ln(1+u)? Expand it then set u=sinx.

then what we do for solving sin series squre

and then how we solve squre of sin series

then what we do for solving sin series squre

then what we do for solving sin series squre

Thread is 12 years old. Please don't resurrect old threads.

Thread is 12 years old. Please don't resurrect old threads.

So solve ln(1+sinx)

So solve ln(1+sinx)

Make a new thread, this thread is almost 13 year olds.

(edited 6 years ago)

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