Two atomic clocks are carefully synchronized. One remains in New York, and the other is loaded on an airliner that travels at an average speed of u = 250 m/s and then returns to New York. When the plane returns, the elapsed time on the clock that stayed behind is 4 hours. By how much will the reading of the two clocks differ, and which clock will show the shorter elapsed time? (Hint : Since u << c, you can simplify sqrt(1 ? u2/c2) by a binomial expansion).
ok so i think i have this right, but im confused as to which should be the rest frame and which should be the moving frame, i.e which should be t and whcih should be t'.
I used gamma ~ 1-(u2/c2)/2
then said that t=4 hours and t' =?
then used t'=t/gamma
so i ended up with t'-t=-5x10-9s
is this the right way around, i.e the moving clock should have a longer time? i dont think that is right....
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