The Student Room Group
Reply 1
silly_billy
(b) the eq of the curve is y = 4x+c/4x-c where c is a non zero constant. show by differentiation that this curve has no stationary points


y = 4x+c/4x-c
dy/dx = [(4x-c).d[4x+c]/dx - (4x+c).d[4x-c]/dx] / (4x-c)²
........ = [4(4x-c) - 4(4x+c)] / (4x-c)²
........ = 4[4x-c - 4x-c] / (4x-c)²
........ = -8c / (4x-c)²

sub (dy/dx = 0)...
........ = -8c / (4x-c)² = 0

But in the question, it mentions that c is a non-zero constant, if it is not equal to 0, then this equation has no solutions hence, no stationary points.
Reply 2
a) use product rule to find when dy/dx = 0

b) quotient rule...

post if you need more help.
Reply 3
silly_billy
1. (a) Find the stationary point of the curve y=xlnx


y = xlnx
dy/dx = x.d[lnx]/dx + d[x]/dx.lnx (*By product rule)
....... = 1 + lnx

sub (dy/dx = 0), to find stationary points...
...... 1 + lnx = 0
...... lnx = -1
...... x = 1/e
Reply 4
Thanks again!
Original post by Dekota
y = 4x+c/4x-c
dy/dx = [(4x-c).d[4x+c]/dx - (4x+c).d[4x-c]/dx] / (4x-c)²
........ = [4(4x-c) - 4(4x+c)] / (4x-c)²
........ = 4[4x-c - 4x-c] / (4x-c)²
........ = -8c / (4x-c)²

sub (dy/dx = 0)...
........ = -8c / (4x-c)² = 0

But in the question, it mentions that c is a non-zero constant, if it is not equal to 0, then this equation has no solutions hence, no stationary points.

thanks bro

u solved a question when i was barely even born that became very useful 14 yrs into the future
(edited 4 years ago)