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    I'm as good as stuck with this one.
    \text 8\pi\int_{0}^{\infty}\frac{t^3}{  (4+t^2)^\frac{5}{2  }} dt
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    Are you really 11? If so you are genious eventhough you can't do this question
    -----
    Unparseable or potentially dangerous latex formula. Error 4: no dvi output from LaTeX. It is likely that your formula contains syntax errors or worse.
    t^3 = t(t^2 + 4) - 4t\\

    So\ \frac{t^3}{52(t^2 + 4)} = \frac{t}{52} - \frac{4t}{52(t^2+4)

    I guess you can do it from now, as I believed you are genious
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    (Original post by BCHL85)
    Are you really 11? If so you are genious eventhough you can't do this question
    -----
    Unparseable or potentially dangerous latex formula. Error 4: no dvi output from LaTeX. It is likely that your formula contains syntax errors or worse.
    t^3 = t(t^2 + 4) - 4t\\

    So\ \frac{t^3}{52(t^2 + 4)} = \frac{t}{52} - \frac{4t}{52(t^2+4)

    I guess you can do it from now, as I believed you are genious
    *Genius

    He's bluffing, his actual age is 16.
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    Aha, now we have another genious here, 1 year old that can read + type
    lol.
    He's bluffing or you are?
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    (Original post by BCHL85)
    Aha, now we have another genious here, 1 year old that can read + type
    lol.
    He's bluffing or you are?
    *Genius

    Lol, I believe we both are. Or perhaps I'm one precocious little child? Who knows?
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    sorry, keeping my mistake on genius :p:
    well, at least you are genius in bluffing
    lol
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    (Original post by BCHL85)
    sorry, keeping my mistake on genius :p:
    well, at least you are genius in bluffing
    lol
    I concur.

    You're probably better than me at Mathematics, consider that an accolade.
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8\pi\int_0^{\infty}\frac{t^3}{(4  +t^2)^{5/2}}dt         =

\frac{8\pi}{2}\int_4^{\infty}\fr  ac{x-4}{x^{5/2}}dx \\ =

4\pi\int_4^{\infty}x^{-5/2}(x-4)dx                         \\ =

4\pi\int_4^{\infty}(x^{-3/2}-4x^{-5/2})dx              \\ =

4\pi\left(8/3x^{-5/2}-2x^{-1/2}\right)_4^{\infty}     \\ =

4\pi\left(-(1/3-1)\right)                                          \\ =

\frac{8\pi}{3}
 
 
 
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