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    Simplify:

    √(x^4) y^3 / x^2 3√(y^6)

    The square root of x to the power 4, times y-cubed ALL OVER x squared, times the cube root of y to the power 6

    its just that i do not know the rule for omitting the 3√ from the 3√(y^6).

    Help appreciated!
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    that is not an easy question, i do A level maths and have absolutly no idea what to do.
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    lol well i'm doing 1st year degree maths...

    it's about cancelling the indices using the usual rules, x³ times x³ = x^6 etc etc

    the answer is apparently just y. but i dont see why (no pun intended)
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    (Original post by Reloaded)
    Simplify:

    ?(x^4) y^3 / x^2 3?(y^6)

    The square root of x to the power 4, times y-cubed ALL OVER x squared, times the cube root of y to the power 6

    its just that i do not know the rule for omitting the 3? from the 3?(y^6).

    Help appreciated!
    To find square root divide power by 2.
    To find cube root divide power by 3
    The cube root of x to the power of 12 is x to the power of 4
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    (Original post by steve2005)
    To find square root divide power by 2.
    To find cube root divide power by 3
    The cube root of x to the power of 12 is x to the power of 4
    ohhhhhh seeeeen...
    yes it makes sense now. i wasnt aware of the "To find cube root divide power by 3" etc rule.

    Thanks all.
 
 
 
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