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    Attached in the attachment is their solution, and here is mine. Tell me if i really have, or whether i am being a complete idiot (usually the case)

    The question is :

    5x³ + 8
    x(x-2)

    Firstly i divided it as it is an improper fraction, and i got (x² - 2x)(5x+10) remainder 10x +8

    So, A(x-2) + B(x) = 10x+8
    x=2
    2B = 28
    B=14

    if x = 0
    -2A= 8
    A=-4

    Therefore, 5x +10 -4/x + 14/(x-2)

    Thanks for looking over it.
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    Your solution is incorrect, theirs is correct.
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    (Original post by Library)
    Attached in the attachment is their solution, and here is mine. Tell me if i really have, or whether i am being a complete idiot (usually the case)

    The question is :

    5x³ + 8
    x(x-2)

    Firstly i divided it as it is an improper fraction, and i got (x² - 2x)(5x+10) remainder 10x +8

    So, A(x-2) + B(x) = 10x+8
    x=2
    2B = 28
    B=14

    if x = 0
    -2A= 8
    A=-4

    Therefore, 5x +10 -4/x + 14/(x-2)

    Thanks for looking over it.

    your remainder should have been 20x + 8
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    *Suprised* why?... what have i done wrong?
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    you can check to see if it is working by putting a value for x into both versions...eg if x=3 then the first version is worth 143/3 but the second version is worth 113/3 so there must be an error somewhere.
 
 
 

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